Question 763746
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Distance equals rate times time, so distance divided by time is rate.  With head wind, ground speed is air speed MINUS wind speed. With tail wind, ground speed is air speed PLUS wind speed.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r_a\ -\ r_w\ =\ \frac{180}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r_a\ +\ r_w\ =\ \frac{180}{1.2}]


Note:  6 minutes is 0.1 hour.


Solve the 2X2 system for *[tex \LARGE r_a] and *[tex \LARGE r_w]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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