Question 763735
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Any equation of the form *[tex \LARGE x\ =\ \alpha] is a vertical line.  Any line perpendicular to a vertical line is a horizontal line.  Horizontal lines have the characteristic that every point on the line has exactly the same *[tex \LARGE y]-coordinate.  Since the desired line passes through *[tex \LARGE \left(2,\,7\right)], which has a *[tex \LARGE y]-coordinate of 7, every point on the line must have a *[tex \LARGE y]-coordinate equal to 7.  The slope of a horizontal line is 0.  The *[tex \LARGE y]-intercept must, since it is also on the line, have a *[tex \LARGE y]-coordinate of 7, hence the *[tex \LARGE y]-intercept is the point *[tex \LARGE \left(0,\,7\right)].  Write a slope-intercept equation where the slope is 0 and the *[tex \LARGE y]-coordinate of the *[tex \LARGE y]-intercept is 7.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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