Question 763708


x^3 + 8y^3


x^3 + (2y)^3


(x + 2y)(x^2 - x*2y + (2y)^2) ... use the sum of cubes factoring rule


(x + 2y)(x^2 - 2xy + 4y^2)


Final Answer: (x + 2y)(x^2 - 2xy + 4y^2)