Question 763438
log 3exponent,2x+log 3exponent (2x-1 ) +1equals 0
{{{log(3^(2x))+log(3^(2x-1))+1=0}}}
{{{log((3^(2x)*3^(2x-1)))=-1}}}
{{{log(3^((4x-1)))=-1}}}
convert to exponential form
{{{3^(4x-1)=10^-1}}}
take log of both sides
(4x-1)log3=-1log10=-1
4x-1=-1/log3=-1/0.4771=-2.0960
4x=-1.0960
x=-0.2740
This ans checks out ok. Try it yourself for a good exercise in algebra.