Question 763575
in 5 years time a father will be twice as old as his son will be. four years ago he was three times as old as his son was. find their present ages?
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4 yrs ago:
x=son's age
3x=father's age
..
At present
x+4=son'age
3x+4=father's age
..
5 yrs from now:
x+4+5=x+9=son'age
3x+4+5=3x+9=father's age
3x+9=2(x+9)
3x+9=2x+18
x=9
son's present age=x+4=13
father's present age=3x+4=31