Question 763337
a father is now twice in age to his son.20 years ago he was 12 times as old as his son.the present age of the father is
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let x=son's present age
2x=father's present age
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20 yrs ago:
x-20=son's age
2x-20=father's age
2x-20=12(x-20)
2x-20=12x-240
10x=220
x=22
2x=44
father's present age=44