Question 763285
Find the solution set of logarithm of x base3 + logarithm of (2x-3) base3 = 3
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{{{log(3,x) + log(3,2x-3) = 3}}}
{{{log(3,x*(2x-3)) = 3}}}
{{{3 = log(3,3^3)}}}
x(2x-3) = 27
{{{2x^2 - 3x - 27 = 0}}}
(2x - 9)(x + 3) = 0
x = -3 not allowed --> log of negative
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x = 9/2