Question 64680
The given equations are: 


{{{(1/2)x + (3/5)y = (3/2)}}}    -------------> (1)



{{{(-1/4)x - (1/8)y = (1/8)}}}   -------------> (2) 



Multiply EQN (1) by {{{(1/2)}}}, we get: 




{{{(1/4)x + (3/10)y = (3/4)}}}    -------------> (3) 




Adding (2) and (3), we get: 



{{{(7/40)y = (7/8)}}} 



Hence, y = {{{(7/8) * (40/7)}}} 



This implies, y = 5  



Now, substituting for y in any of the above equations, either in (1) or (2) we get the value of x.



So substituting for y in (1), we get: 



{{{(1/2)x + (3/5)*5 = (3/2)}}} 



{{{(1/2)x + 3 = (3/2)}}} 



{{{(1/2)x = (3/2) - 3}}} 



{{{(1/2)x = -(3/2)}}} 



This implies,


x = -{{{(3/2) * (2/1)}}}


x = -3 



Hence, the solution.