Question 65745
180 = -16t^2 + 112t
0 = -16^2 + 112t - 180
From here, you could use quadratic formula: {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
for ~> ax^2 + bx + c
where:
a = -16
b = 112
c = -180
Or, you could just use solving cubes....
180 = -16t^2 + 112t
-11.25 = t^2 - 7t
1 = (t - 3.5)^2
3.5 +- 1 = t
t = 4.5 seconds and t = 2.5 seconds