<PRE><B>Question 763182</B>
Solve using logs 3^2n = 3*6^n+3. Please show your work.
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2n*log(3) = log(3) + (n+3)*log(6) = log(3) + n*log(6) + 3*log(6)
2n*log(3) - n*log(6) = log(3) + 3log(6)
n*(2log(3) - log(6)) = log(3) + 3log(6)
n = (log3 + 3log6)/(2log3 - log6) (as below)
n = log(648)/log(1.5)
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I somehow got n= (2log3 - log2)/(3log6), however, 
the correct answer is n= (log3 + 3log6)/(2log3 - log6)
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