Question 65741
{{{A = A[0]e^(-.18t)}}}
{{{40 = A[0]e^(-.18*3)}}}
{{{A[0] = 40*(1/e^(-.54))}}}
{{{ln(A[0]) = ln(40) + .54}}}
{{{ln(A[0]) = 3.689 + .54}}}
{{{ln(A[0]) = 4.229 }}}
{{{A[0] = 68.649}}} grams answer