Question 763079
In the set of 5 numbers, one is already fixed i.e. 23.

So we need to find out how many possible combinations are there for the remaining 4 numbers in the set.

In other words, how many ways can 4 numbers be chosen from a set of 36? (Note that it is only 36 and not 37 - because the number 23 is already chosen).

The answer is 36 choose 4 or C(36,4) = 36*35*34*33/1*2*3*4 = {{{highlight(58905)}}} ways.


:)