Question 763120


{{{3^(x+4)=27^(2x)}}}.......since {{{27^(2x)=(3^3)^(2x)=3^(6x)}}}, we have


{{{3^(x+4)=3^(6x)}}}...if bases equal then exponents have to be equal too

so, we will have

{{{x+4=6x}}}...solve for {{{x}}}

{{{4=6x-x}}}

{{{4=5x}}}

{{{4/5=x}}}