Question 64611
Verify that the points P(0,0) and Q(a,0) and R(a/2,a/2) form the vertices of a right triangle. Work in terms of a.
DISTANCE AB WHERE A IS(X1,Y1) AND B IS (X2,Y2)=D
D^2=(X2-X1)^2+(Y2-Y1)^2...SO
PQ^2=A^2+0=A^2
QR^2=(A/2)^2+(A/2)^2=2*A^2/4=A^2/2
PR^2=(A/2)^2+(A/2)^2=A^2/2
HENCE PQ^2=QR^2+PR^2
HENCE PQR IS R.A.T.WITH ANGLE PRQ=90