Question 762650
{{{
(x-y)^2 = x^2 - 2 xy + y^2
}}}

{{{
(x+y)^2 = x^2 + 2 xy + y^2
}}}

subtracting...
{{{
(x-y)^2-(x+y)^2 = -4xy 
}}}

and so...


{{{
(x-y)^2 =(x+y)^2 -4xy = (14+10)^2-4(14)(10)=16
}}}

So x-y=4



:)