Question 762767
let the three  consecutive even integer are x-2,x,x+2
Five times the first 3 consecutive even integer is 4 less than the twice of the sum of 2nd and 3rd . 
so 5[x-2]=2[x+x+2]-4
or 5x-10=4x+4-4
or x=10
so the three even numbers are 8,10,12