Question 65704
FIRST YOU MUST RESOLVE THE ITEMS WITHIN THE ( )
(X-5)^2=X^2-10X+25 NOW MULTIPLY THIS BY 2
2(X^2-10X+25)=2X^2-20X+50 NOW SET THIS =3
2X^2-20X+50=3 NOW SUBTRACT 3 FROM BOTH SIDES
2X^2-20X+50-3=0
2X^2-20X+47=0 THIS EQUATION DOESN'T FACTOR NORMALLY THUS WE NEED THE QUADRATIC EQUATION TO FIND THE X VALUES THUS
X=(-B+-SQRT[B^2-4AC])/2A
X=(20+-SQRT[400-4*2*47])/2*2
X=(20+-SQRT[400-376])/4
X=(20+-SQRT[24])/4
X=(20+-4.899)/4
X=(20+4.899)/4
X=6.22 SOLUTION
X=(20-4.899)/4
X=15.101/4
X=3.77 SOLUTION