<PRE><B>Question 762740</B>
 The sum of the reciprocals of 2 consecutive odd integers is 16/63. Find the numbers. 
I was thinking that the equation was 1/x + 1/x+2= 16/63 
----
1st odd number: x-1
2nd odd number: x+1
-----
1/(x-1) + 1/(x+1) = 16/63
------
Multiply thru by 63(x-1)(x+1) to get:
63(x+1) + 63(x-1) = 16(x^2-1)
------------------------------------
126x = 16x^2 - 16
16x^2 - 126x - 16 = 0
----
8x^2 - 63x - 8 = 0
(x-8)(8x+1) = 0
----
Whole number solution:
x = 8
====
1st odd number: 2x-1 = 15
2nd odd number: 2x+1 = 17
==============================
Cheers,
Stan H.</PRE>