Question 762740
Consecutive ODD numbers,  {{{2x+1}}} and {{{2x+3}}}.
Without the factor 2, each of the numbers may be either odd or even.


NOW, {{{1/(2x+1)+1/(2x+3)=16/63}}} and you can solve according to number properties which you have been studying.  Start by multiplying lefthand and righthand members by the LCD, which is {{{63(2x+1)(2x+3)}}}.