<PRE><B>Question 762706</B>
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Area is *[tex \LARGE lw].  But *[tex \LARGE l\ =\ 2w\ +\ 1], so *[tex \LARGE A(w)\ =\ 2w^2\ +\ w].  If *[tex \LARGE A\ =\ 45\text{yd}^2] then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2w^2\ +\ w\ =\ 45]


Put the quadratic into standard form and solve for *[tex \LARGE w].  Discard the absurd negative root.  Then calculate *[tex \LARGE 2w\ +\ 1]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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