Question 762593
Find each year's result year-by-year for 2 years.

Year 1:  {{{1800-0.29*1800}}}
Year 2:  {{{(1800-0.29*1800)-0.29*(1800-0.29*1800)}}}


Calculate from that, or try to simplify first if you want.
{{{1800-0.29*1800-0.29*1800+0.29^2*1800}}}
{{{1800-1800*0.29-1800*0.29+1800*0.29^2}}}
{{{1800-2*1800*0.29+1800*0.29^2}}}
{{{1800(1-2*0.29+0.29^2)}}}  That shows a factorable trinomial-like expression.
{{{1800(1-0.29)^2}}}


RESULT:  $907.38