Question 762600
w and h dimensions of the rectangle.

Area, {{{wh}}}.


{{{h+h/5}}} and {{{w-w/5}}} are the new dimensional values 
makes area now of this rectangle {{{(w-w/5)(h+h/5)}}}.


{{{((5w-w)/5)((5h+h)/5)=(4w/5)(6h/5)=highlight(((4*6)/(5^2))(wh))}}}


Appears to be an area decrease, {{{24/25}}} of the original area.