Question 762544
Carbon dating. The amount of the carbon 14 present in animal bones after t year is given as P(t)= Poe^-0.0012t. A bone has lost 30 % of its carbon 14. How old is the bone?
------
P(t)= Poe^-0.0012t
------
Solve: e^(-0.0012t) = 0.30
Take the natural log:
-0.0012t = ln(0.3)
-----
-0.0012t = -1.2040
t = 1003.31 years
====================
Cheers,
Stan H.
=======================