<PRE><B>Question 762540</B>
The manager of a small business hires a consultant to help determine how the manager can improve the employees&#39; morale. Currently there are 8 employees who like their job (have high morale) and 6 who do not like their job (have low morale). The consultant randomly selects 3 workers to interview. What is the probability the consultant selects three employees who like their job?
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# of ways to succeed: 8C3 = (8*7*6)/(1*2*3) = 56
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# of random groups of three: 14C3 = 14*13*12/1*2*3 = 364
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P(3 who like their job) = 56/364 = 0.1538
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Cheers,
Stan H. 
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