Question 762529
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The equation of a circle centered at *[tex \LARGE (h,k)] with radius *[tex \LARGE r] is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ h)^2\ +\ (y\ -\ k)^2\ =\ r^2]


You are given the center, and the radius is the distance from the center to any point on the circle, one of which you were given.


Use the following modification of the distance formula to find the radius squared.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r^2\ =\ (x_1\ -\ x_2)^2\ +\ (y_1\ -\ y_2)^2]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates the given center and given point on the circle.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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