Question 65710
3x^2 - 2x + 1 = 0

Here a = 3;  b = -2 ;   c = 1

{{{x=(-b+-sqrt(b^2-4a*c))/(2*a)}}} 

{{{x=(2+-sqrt(4-4*3*1))/(2*3)}}}

{{{x=(2+-sqrt(-8))/(6)}}}
Taking out 2 and cancelling,

{{{x=(1+-sqrt(-2))/3}}}


Good Luck!!!