Question 762321
The equation of a line is Y = mX + B.
Where m is the slope and B is the Y-intercept.
Given m = -4/3 and the point (-4,-2).
When X = -4, then Y = -2.
Plug these values into the equation of a line and solve for B.
Y = mX + B
{{{-2 = (-4/3)*(-4) + B}}}
Simplify.
{{{-2 = (16/3) + B}}}
Convert -2 to thirds by multiplying it by 3/3.
-2 * 3/3 = -6/3
{{{-6/3 = 16/3 + B}}}
Subtract 16/3 from both sides.
{{{highlight(-22/3 = B)}}}
So the equation of the line is {{{Y = (-4/3)X - 22/3}}}