<PRE><B>Question 762173</B>
&lt;pre&gt;
This gives us this division puzzle to solve,
to figure out what the digits A,B,C,D,E,F,G,
must be in the divisions below. Of course we 
only need A. 

  &lt;u&gt;  B&lt;/u&gt;             &lt;u&gt;  E&lt;/u&gt;
2A)71    and    2A)94
   &lt;u&gt;CD&lt;/u&gt;              &lt;u&gt;FG&lt;/u&gt; 
    2               2

We see right off that CD=69
and FG=92, to give the remainder 2:

  &lt;u&gt;  B&lt;/u&gt;             &lt;u&gt;  E&lt;/u&gt;
2A)71    and    2A)94
   &lt;u&gt;69&lt;/u&gt;              &lt;u&gt;92&lt;/u&gt;
    2               2

So B=3 in order to get the 6 digit of 69.
And E=4 in order to get the 9 digit of 92 
(with 1 to carry)

  &lt;u&gt;  3&lt;/u&gt;             &lt;u&gt;  4&lt;/u&gt;
2A)71    and    2A)94
   &lt;u&gt;69&lt;/u&gt;              &lt;u&gt;92&lt;/u&gt;
    2               2

Now we see that A=3 to get the 9 digit of 69,
and also to get the 2 digit of 92.

  &lt;u&gt;  3&lt;/u&gt;             &lt;u&gt;  4&lt;/u&gt;
23)71    and    23)94
   &lt;u&gt;69&lt;/u&gt;              &lt;u&gt;92&lt;/u&gt; 
    2               2

So the answer is 23.

Edwin&lt;/pre&gt;
</PRE>