Question 762284


{{{sqrt(3y+7)= y+1}}}....square both sides

{{{(sqrt(3y+7))^2= (y+1)^2}}}

{{{3y+7= y^2+2y+1}}}

{{{0= y^2-3y+2y+1-7}}}

{{{y^2+2y-3y-6=0}}}.....group to factor

{{{(y^2+2y)-(3y-6) = 0}}}

{{{y(y+2)-3(y-2) = 0}}}

{{{(y-3)(y+2) = 0}}}

solutions:

if {{{(y-3) = 0}}} => {{{y=3}}}

if {{{(y+2) = 0}}} => {{{y=-2}}}