<PRE><B>Question 762268</B>
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You have 20 liters of 15% acid, so there are *[tex \LARGE 0.15(20)\ =\ 3] liters of pure acid in the 20 liters you have.


If there are *[tex \LARGE x] liters of 40% acid, there are *[tex \LARGE 0.4x] liters of pure acid that are being added.


Once you add *[tex \LARGE x] liters to 20 liters, you have *[tex \LARGE x\ +\ 20] liters, and you want there to be *[tex \LARGE 0.25(x\ +\ 20)] liters of pure acid in the mixture.


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.4x\ +\ 3\ =\ 0.25(x\ +\ 20)]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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