Question 762139
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Total children:  53


Children that had neither:  8


Children that had something:  53 - 8 = 45


Children that had ice cream plus children that had cold drinks = 30 + 23 = 53.


53 is 8 more than 45, so 8 of the children must have been counted twice when adding the 30 plus the 23.  Hence, 8 had both.  If 30 had ice cream and 8 had both, then 30 minus 8 = 22 had ice cream only.  If 23 had cold drinks and 8 had both, then 23 minus 8 = 15 had cold drinks only.


Check:


22 ice cream only


15 cold drink only


8 both


8 nothing


22 + 15 + 8 + 8 = 53


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
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