Question 762204
<pre>
Frequency = {{{1/(period)}}}
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Period of y = tan({{{pi/3}}}x) 
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period of y = A·tan(Bx) is {{{pi}}}÷B
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So the period of y = tan({{{pi/3}}}x) is {{{pi}}}÷{{{pi/3}}} = {{{pi}}}·{{{3/pi}}} = {{{cross(pi)}}}·{{{3/cross(pi)}}} = 3
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frequency = {{{1/(period)}}} = {{{1/3}}} 
Edwin</pre>