Question 762070
y+3=-1/2(x-2)^2 how to graph the parabola

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The equation is in vertex form:
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Vertex is at (2,-3)
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The form indicates the parabola is opening downward because of the "-1/2"
coefficient in the x^2 term.
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The y-intercept is (0,-5)
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{{{graph(400,400,-10,10,-10,10,(-1/2)(x-2)^2-3)}}}
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Cheers,
Stan H.
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