Question 761923
find the maximum and minimum values of a function 2x^3-3x^2-12x+8
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{{{f(x) = 2x^3-3x^2-12x+8}}}
f'(x) = {{{6x^2 - 6x - 12 = 0}}}
{{{x^2 - x - 2 = 0}}}
x = -1, 2
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f(-1) = 15
f(2) = -12