Question 65663
Use the "Product rule" for logarithms: {{{logM + logN = log((MN))}}}
Also recall that {{{a*log((x)) = log((x))^a}}}
Applying this to your case:
{{{log((y+5)) + 2*log((x+1)) = log((y+5)) + log((x+1))^2}}} = {{{log(((y+5)(x+1)^2))}}}