<PRE><B>Question 754504</B>
Solve the system of equations and give the value of x.

8x = 23 + 7y
2x + 4y = 0


2x + 4y = 0

Divide each item by 2

Therefore:

x + 2y = 0

Subtract 2y from each side of the equation.

x + 2y - 2y = 0 - 2y

x = -2y


Rearrange equation 1:

8x = 23 + 7y

Subtract 7y from each side of the equation

8x - 7y = 23 + 7y - 7y

8x - 7y = 23

Substitute x = -2y into equation 1

8(-2y) - 7y = 23

-16y - 7y = 23

-23y = 23

Divide each side by -23

y = -1


We already have:

x = -2y

Therefore:

x = -2(-1)

x = 2


Check:

8x - 7y = 23

8(2) - 7(-1) = 23

16 - (-7) = 23

- (-7) = +7

16 + 7 = 23

23 = 23



Check:

2x + 4y = 0

2(2) + 4(-1) = 0

4 + (-4) = 0

4 - 4 = 0





Answer:

x = 2 and

y = -1









Lennox Obuong
Algebra Tutor
Nairobi, Kenya
Email: lennoxobuong@yahoo.com</PRE>