Question 745172
{{{5^(x-1)=7^(1-x)}}}


{{{5^(x-1)=7^(-(x-1))}}}

{{{5^(x-1)*7^(x-1)=1}}}

{{{35^(x-1)=1}}}

{{{35^(x-1)=35^0}}}

{{{x-1=0}}}

{{{x=1}}}


:)