Question 761541
FIrst number is 10 less than 5 times second number.

Let second number be x
First number is then 5*x - 10

Product = {{{x * (5*x - 10) = 120}}}

{{{5*x^2 - 10*x - 120 = 0}}}


{{{x^2 - 2*x - 24 = 0}}}

Solving for x, x = +6 or -4.
First number can be 20 or -30
Possible solutions are (20,6) and (-30,-4)

Solution for the above quadratic equation is shown through solver below.

*[invoke quadratic "x", 1, -2, -24]