<PRE><B>Question 761619</B>
This problem can be solved by adding the vectors together and then drawing a right triangle.
1 miles East + 2 miles East = 3 miles East
Since the North distance is larger, we will call North positive.
9 miles North - 5 miles South = 4 miles North.
{{{drawing(200,200,-4,4,-4,4,
triangle( -1, -2, 2, -2, 2, 2 ),
  locate( -0.5, -2, 3miles ), locate( 2.25, 0, 4miles ), locate( -.25, 0, C ))}}}

Now you can use the Pythagorean theorem to find C:

{{{C^2=A^2+B^2}}}
{{{C^2=3^2+4^2}}}
{{{C^2=9+16}}}
{{{C^2=25}}}
{{{sqrt(C)=sqrt(25)}}}
{{{highlight(C=5)}}}
He is now 5 miles from the starting point.
</PRE>