Question 761451
Let d = distance fallen in feet and
Let t = fall time in seconds and
Let c = constant of direct proportionality in feet per seconds squared.
The formula to use is
(1) d = c*t^2
Where we are given
(2) 63 = c*8^2 or
(3) c = 63/64
Then in 10 seconds the distance is given by
(4) d = 63/64*(10)^2 or
(5) d = 6300/64 or
(6) d = 98.4375
Answer: the constant of variation is 63/64 and the distance dropped in ten seconds is 98 feet.