Question 761258
Ten quarters dated 1990 through 1999 are tossed. Find the probability of the following events.
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Binomial Problems with n = 10 and p(head) = 1/2
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a) P(heads on 1995 quarter only)______?
# of ways to succeed: 1*2^9
# of possible outcomes: 2^10
P(heads on 1995 quarter only) = (1*2^9)/(2^10) = 1/2
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b) P(heads on all 10 quarters)= (1/2)^10 = 1/1024
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c) P(exactly 2 heads)= 10C2(1/2)^10 = 45/1024
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d) P(at least three heads)= 1 - binomcdf(10,1/2,2) = 0.0547
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Cheers,
Stan H.
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