Question 761179
While trying to think how to analyze this, no way seems possible without using the density of copper.  


Use 8.96 grams/cm^3 for copper.

This density is {{{8.96 * (1/1000)*(100*100*100)*(1/m)(1/m)(1/m)=highlight(8960)}}} {{{highlight(kg/m^3)}}}


That conversion is to let us use units of only kilograms and meters, or cubic meters.


Let h = depth of the disc.
Volume of the disc is {{{h*pi*(0.243)^2}}} {{{m^3}}} .
This volume, based on the mass and density of the copper must be:
Volume is {{{62*(1/8960)}}} m^3


Those two volumes must be equal.
{{{highlight(h*pi*(0.243)^2=62/8960)}}}
And of course you just solve for h.