Question 760742
evaluate:
log 5(base 2)/log 11(base 2)-log 5(base 4)/log 11(base 4)
{{{log(2,(5))/log(2,11))}}}-{{{log(4,(5))/log(4,(11))}}}
convert 2nd term to base 2
{{{log(4,(5))/log(4,(11))}}}
{{{(log(2,(5))/log(2,(4)))/(log(2,(11))/log(2,(4)))=(log(2,(5)))/(log(2,(11)))}}}
{{{log(2,(5))/log(2,11))}}}-{{{log(4,(5))/log(4,(11))}}}
={{{log(2,(5))/log(2,11))}}}-{{{log(2,(5))/log(2,(11))}}}=0