Question 760934
The slope of the given line {{{y = 3x - 7}}} is {{{m=3}}}
The slope of the perpendicular line is {{{m[1]=-1/m=-1/3}}}
The equation of the line {{{y-y[0]=m(x-x[0])}}}
Since line passes through the point  (2,-6), substitute into the formula {{{x[0]=2}}}, {{{y[0]=-6}}}
{{{y-(-6)=(-1/3)(x-2)}}} 
{{{y+6=-(1/3)x+2/3}}}
{{{y=-(1/3)x-16/3}}} the equation of the line that is perpendicular to line {{{y = 3x - 7}}}
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The slope of the parallel line is {{{m[2]=m=3}}}
The equation of the line {{{y-y[0]=m(x-x[0])}}}
Since line passes through the point  (2,-6), substitute into the formula {{{x[0]=2}}}, {{{y[0]=-6}}}
{{{y-(-6)=3(x-2)}}} 
{{{y+6=3x-6}}}
{{{y=3x-12}}} the equation of the line that is parallel to line {{{y = 3x - 7}}}