Question 760887
f(x) = x^2 - 4x - 5
Factorise
 (x - 5)(x + 1) = 0
 x - 5 = 0
     x = 5
 x + 1 = 0
     x = -1
This where the parabola cuts the x axis (-1,0) and (5,0)
f(x) = x^2 - 4x - 5
To find where it cuts the y axis make x = 0
 f(0) = 0^2 -4(0) - 5
   So parabola cuts y axis at (0, -5)
To find the vertex.
The distance between x = -1 and x = 5
(where it cuts the x axis) is 6 units
Half of 6 = 3
So either add 3 to -1 = 2
 or subtract 3 from 5 = 2
Now this shows that the axis of symmetry is
 x = 2
Now put x =2 into the equation
f(x) = x^2 - 4x - 5
     = (2)^2 - 4(2) - 5
     = 4 - 8 - 5
     = -9
This is the y coordinate of the vertex
      (2, -9)
I hope this helps you.
:-)