Question 760787
<pre>
8x³+4x²-2x-1

Factor 4x² out of the first two terms:

4x²(2x+1)-2x-1

Factor -1 out of the last two terms:

4x²(2x+1)-1(2x+1)

Now there are just two terms. Factor (2x+1) out of those 
two terms:

(2x+1)(4x²-1)

Factor the second factor as the difference of two squares:

(2x+1)(2x-1)(2x+1)

and since the (2x-1) appears twice as a factor:

(2z+1)²(2x-1)

Edwin</pre>