Question 760563
{{{t^2 + t/2 + 1/16}}}

= 

{{{t^2 + t/4 + t/4 + 1/16}}} .... split the t/2 into t/4 and t/4

=

{{{t*(t+1/4) + (1/4)*(t+1/4)}}} .... t is a common factor for 1st 2 terms, 1/4 for the second 2 terms

=

{{{(t+(1/4))*(t+(1/4))}}}

=

{{{(t+(1/4))^2}}}

The two factors are {{{t+(1/4))}}}, {{{t+(1/4))}}}

:)