Question 760414
{{{y=7x-10}}}....eq.1
{{{y=-3}}}....eq.2
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start with {{{y=-3}}}....eq.2, substitute in eq.1

{{{-3=7x-10}}}....eq.1

{{{-3+10=7x}}}

{{{7=7x}}}

{{{7/7=x}}}

{{{1=x}}}


 {{{drawing( 600, 600, -10, 10, -15, 10,circle(1,-3,0.15),locate(1,-3,p(1,-3)), graph( 600, 600, -10, 10, -15, 10, -3,-3, 7x-10)) }}}