Question 760401
Class records at a certain college indicate that a student selected at random has a probability of 0.77 of passing Accounting 1. If that student passes Accounting 1, the probability that they will pass Accounting 2 is .90. What is the probability that they will pass both classes? 
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P(pass 1) = 0.77

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P(pass 2 | pass 1) = 0.90
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P(pass 1 AND pass 2) = P(pass 2 | pass 1)*Pass(1) = 0.90*0.77 = 0.6930
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Cheers,
Stan H.
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