<PRE><B>Question 65621</B>
I need help to find an exponential function of the form f(x)=ba^x+c with y-intercept 2, horizontal asymptote y=-2, that passes through the point P(1,4).
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If y-int = 2, f(0)=ba^0+c
=b+c=2
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If horizontal asymptote is y=-2, then c=-2
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Then b-2=2
b=4
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Now, y=4a^x-2
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If y=4 when x=1, 
4=4a^(1)-2
4=4a-2

4a=6
a=3/2
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EQUATION:
y=4(3/2)^x-2
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Cheers,
Stan H.




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